-y+28+y^2=2y+y^2

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Solution for -y+28+y^2=2y+y^2 equation: 



-y+28+y^2=2y+y^2

We move all terms to the left:

-y+28+y^2-(2y+y^2)=0

We add all the numbers together, and all the variables

y^2-(2y+y^2)-1y+28=0

We get rid of parentheses

y^2-y^2-2y-1y+28=0

We add all the numbers together, and all the variables

-3y+28=0

We move all terms containing y to the left, all other terms to the right

-3y=-28

y=-28/-3

y=9+1/3

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